LLDB - am I able to set breakpoint at a function in a process, if the executable was not compiled with -g (ie no debugging info)?
@lolgrep Can you please help with this when you get a chance? Thank you - much appreciated! :]
Yes, you can set a breakpoint on a address if no symbol information is available to you.
Yea, but I meant was, can I do something like
breakpoint set -n main
on an executable that was not compiled with -g flag?
No right? There’s no way at all to do that right?
And a separated but related question - if the -g flag was not used, I won’t be able to inspect and see source code lines as well right? I can only see assembly right?
There’s no way LLDB can do that. Once it starts up, it’ll look for dSYM for a module. If it can find one (or if symbol table info is available for that address) then it will associate a function name to an address. If no, you’ll see the usual
lldb_unammedFooBar123 naming for a function.
However even though there’s no naming, lldb can figure a function is there via the Mach-O
LC_FUNCTION_STARTS load command, which contains a compact format for all functions compiled into the binary
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